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Proof step 1 from proof int2bytes-len-one (conclusion)

⊦ int2bytes(i) = by ' ↔ i = b2i(by)

User applied rule case distinction

And obtained the following new goals

Proof step 2:
int2bytes(i) = by ' ⊦ i = b2i(by)

Rule argument

pos: right 1

Additional information

Used simplifier rules: int2bytes-byte-01: ⊦ int2bytes(b2i(by)) = by ';% ⊦ by ' = by0 ' ↔ by = by0;