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Proof step 10 from proof int2bytes-len-pos-01 (previous step)

# int2bits(j) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0, n = 0, 0 ≤ i, j < 2 ^ (8 * (i + 1)), 2 ^ (8 * (i + 1) - 1) ≤ j ⊦ m = i→n(i + 2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# int2bits(j) = m * 8, 0 ≤ i, j < 2 ^ (8 * (i + 1)), 2 ^ (8 * (i + 1) - 1) ≤ j ⊦ m = i→n(i + 2)

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ 0 + m = m;