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Proof step 18 from proof int2bytes-len-pos-01 (previous step)

# int2bits(j) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0, 0 ≤ i, j < 2 ^ (8 * (i + 1)), 2 ^ (8 * (i + 1) - 1) ≤ j ⊦ n = 0, m + 1 = i→n(i + 2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
# int2bits(j) = m * 8 + n, 2 ^ (8 * (i + 1) - 1) ≤ j, j < 2 ^ (8 * (i + 1)), 0 ≤ i, n < 8 ⊦ m + 1 = i→n(i + 2), n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)