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Proof step 1 from proof int2bytes-len-pos (conclusion)

0 ≤ i, 2 ^ (8 * i) ≤ j, j < 2 ^ (8 * (i + 1) - 1) ⊦ # int2bytes(j) = i→n(i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i, j < 2 ^ (8 * (i + 1) - 1), 2 ^ (8 * i) ≤ j, 8 * i + 1 < 8 * (i + 1) ⊦ # int2bytes(j) = i→n(i) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i < j - i0 ↔ i + i0 < j;%0 ≤ j ⊦ 2 ^ j < 2 ^ j0 ↔ j < j0;% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ 0 ≤ i → i→n(i + 1) = i→n(i) + 1;