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Proof step 32 from proof int2bytes-len-pos (previous step)

# int2bits(j) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0, 0 < j, 8 * i + 1 < 8 * (i + 1), j < 2 ^ (8 * (i + 1) - 1), 0 ≤ i, 2 ^ (8 * i) ≤ j ⊦ m = i→n(i), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
# int2bits(j) = m * 8 + n, 2 ^ (8 * i) ≤ j, 0 ≤ i, j < 2 ^ (8 * (i + 1) - 1), 8 * i + 1 < 8 * (i + 1), 0 < j, n < 8 ⊦ n = 0, m = i→n(i)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)% ⊦ i * j = j * i;