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Proof step 36 from proof int2bytes-len-pos (previous step)

# int2bits(j) = 1, 2 ^ (8 * i) ≤ j, 0 < j, 8 * i + 1 < 8 * (i + 1), j < 2 ^ (8 * (i + 1) - 1), 0 < i ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 ≤ i → (# int2bits(i) = 1 ↔ i = 0) subst: [i] → [j] rotate: F spec: int2bits inst: name: int2bits-len-one

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ 2 ^ i ≤ 0 ↔ i < 0;% ⊦ 0 < i → (i * j < 0 ↔ j < 0);% ⊦ i < j → ¬ j < i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: j