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Proof step 6 from proof int2bytes-minus-256 (previous step)

⊦ bits2bytes(true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false ') = i2b(~1) ' + i2b(0) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ 8 < # bits → bits2bytes(bits) = bits2bytes(firstn(# bits - 8, bits)) + i2b(bits2int(lastn(8, bits)))
Proof step 8:
8 < #(true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false ') ⊦ bits2bytes (firstn (#(true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false ') - 8, true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false ')) + i2b(bits2int(lastn(8, true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false '))) = i2b(~1) ' + i2b(0) '

Rule argument

name: bits2bytes-rec rotate: F subst: [bits] → [ true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false ']

Additional information

Used simplifier rules: ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: true ' + false ' + false ' + false ' + false ' + false ' + false ' + false ' + false '