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Proof step 10 from proof int2bytes-minus-one (previous step)

i2b(i) = i2b(~1), # int2bits(i) ≤ 8 ⊦ i = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127, i ≠ j ⊦ i2b((* i)) ≠ i2b((* j))
Proof step 12:
¬(~128 ≤ i ∧ i ≤ 127 ∧ ~128 ≤ ~1 ∧ ~1 ≤ 127 ∧ i ≠ ~1), i2b(i) = i2b(~1), # int2bits(i) ≤ 8 ⊦ i = ~1

Rule argument

seq: ~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127, i ≠ j ⊦ i2b((* i)) ≠ i2b((* j)) subst: [j, i] → [~1, i] rotate: F spec: byte inst: name: notequal

Additional information

Used terms: ~1, i