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Proof step 13 from proof int2bytes-minus-one (previous step)

i2b(i) = i2b(~1), # int2bits(i) ≤ 8 ⊦ i = ~1, ¬ i < ~128 ∧ ¬ 127 < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ 0 < i → (# int2bits(i) ≤ m ↔ i < 2 ^ (n→i(m) - 1))
Proof step 15:
¬ 0 < i, i2b(i) = i2b(~1), # int2bits(i) ≤ 8 ⊦ i = ~1, ¬ i < ~128 ∧ ¬ 127 < i

Rule argument

seq: ⊦ 0 < i → (# int2bits(i) ≤ m ↔ i < 2 ^ (n→i(m) - 1)) subst: [m, i] → [8, i] rotate: F spec: int2bits inst: name: int2bits-lelen

Additional information

Used simplifier rules: i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; Used terms: 8, i