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Proof step 16 from proof int2bytes-minus-one (previous step)

i2b(i) = i2b(~1), i < 0, i < ~128, # int2bits(i) ≤ 8 ⊦ i = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ i < ~1 → (# int2bits(i) ≤ m ↔ 0 ≤ i + 2 ^ (n→i(m) - 1))

Rule argument

seq: ⊦ i < ~1 → (# int2bits(i) ≤ m ↔ 0 ≤ i + 2 ^ (n→i(m) - 1)) subst: [m, i] → [8, i] rotate: F spec: int2bits inst: name: int2bits-lelen-03

Additional information

Used simplifier rules: ⊦ ~1 < i ↔ 0 ≤ i;% ⊦ ¬ i < j → (i ≠ j ↔ j < i);% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: 8, i