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Proof step 13 from proof int2bytes-not-neg (previous step)

int2bytes(i / 256) ≠ [], b2i(int2bytes(i / 256).first) < 0, 256 ≤ i, 0 ≤ i, 128 ≤ i, 0 < i, ∀ i0. i→n(i0) < i→n(i) → b2i(int2bytes(i0).first) < 0 ∧ 0 ≤ i0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
b2i(int2bytes(i / 256).first) < 0, 0 < i, 128 ≤ i, 0 ≤ i, 256 ≤ i, ∀ i0. i→n(i0) < i→n(i) → b2i(int2bytes(i0).first) < 0 ∧ 0 ≤ i0 → false ⊦

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];% ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)