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Proof step 15 from proof int2bytes-one (previous step)

# int2bytes(i) = 1 ⊦ ¬ 127 < i, ¬ i < 0 ∧ ¬ 127 < i, ¬ i < ~128 ∧ ¬ 128 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
# int2bytes(i) = 1, 128 ≤ i, 0 < i, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i < j ↔ j ≤ i;%i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;