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Proof step 11 from proof int2bytes-rec-case (previous step)

¬ i ≤ ~256 ∧ ¬ ~128 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ int2bytes(i) = i2b(~1) ' + i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i < ~128, ~256 < i, i < 0 ⊦ int2bytes(i) = i2b(~1) ' + i2b(i) '

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)%j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);%j0 ≠ 0, j < j0 ⊦ i < (* j) → i < (* j0);% ⊦ ¬ i ≤ j ↔ j < i;