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Proof step 21 from proof int2bytes-rec-case (previous step)

i < 0, i < ~256 ⊦ i = ~256, i % 256 = 0, int2bytes(i) = int2bytes(i / 256 - 1) + int2bytes(i % 256).last '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ i < ~256 ∧ i % 256 ≠ 0 → int2bytes(i) = int2bytes(i / 256 - 1) + int2bytes(i % 256).last '

Rule argument

name: int2bytes-rec-neg-256-01 rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0); Used terms: i