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Proof step 24 from proof int2bytes-rec-case (previous step)

256 ≤ i, 0 < i, 0 ≤ i ⊦ int2bytes(i) = int2bytes(i / 256) + int2bytes(i % 256).last '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 25:
255 < i ⊦ int2bytes(i) = int2bytes(i / 256) + int2bytes(i % 256).last '

Rule argument

name: int2bytes-rec-pos rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) Used terms: i