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Proof step 7 from proof int2bytes-rec-case (previous step)

¬ i < 128 ∧ ¬ 256 ≤ i, i < ~128 ∨ 128 ≤ i ⊦ int2bytes(i) = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 ≤ i, 0 < i, 128 ≤ i, i < 256 ⊦ int2bytes(i) = i2b(0) ' + i2b(i - 256) '

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;