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Proof step 11 from proof int2bytes-rec-neg-01 (previous step)

¬(# mklist(false, i→n(i * 8)) % 8 = 0 ∧ int2bits(j / 2 ^ (i * 8)) ≠ [] ∧ mklist(false, i→n(i * 8)) ≠ []), j % 2 ^ (i * 8) = 0, 0 < i, j + 2 ^ (i * 8) < 0 ⊦ bits2bytes(int2bits(j / 2 ^ (i * 8)) + mklist(false, i→n(i * 8))) = bits2bytes(int2bits(j / 2 ^ (i * 8))) + fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
j % 2 ^ (i * 8) = 0, 0 < i, j + 2 ^ (i * 8) < 0 ⊦ bits2bytes(int2bits(j / 2 ^ (i * 8)) + mklist(false, i→n(i * 8))) = bits2bytes(int2bits(j / 2 ^ (i * 8))) + fix(i→n(i) + 1, i2b(0) ').rest, i→n(i * 8) % 8 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < i → (i * j = 0 ↔ j = 0);% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ mklist(boolvar, m) = [] ↔ m = 0;% ⊦ int2bits(j) ≠ [];% ⊦ # mklist(boolvar, n) = n;