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Proof step 14 from proof int2bytes-rec-neg-01 (previous step)

# mklist(false, i→n(i * 8)) % 8 = 0 ∧ int2bits(j / 2 ^ (i * 8)) ≠ [] ∧ mklist(false, i→n(i * 8)) ≠ [], j % 2 ^ (i * 8) = 0, 0 < i, j + 2 ^ (i * 8) < 0 ⊦ bits2bytes(int2bits(j / 2 ^ (i * 8))) + bits2bytes(mklist(false, i→n(i * 8))) = bits2bytes(int2bits(j / 2 ^ (i * 8))) + fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
j % 2 ^ (i * 8) = 0, i→n(i * 8) % 8 = 0, 0 < i, j + 2 ^ (i * 8) < 0 ⊦ bits2bytes(mklist(false, i→n(i * 8))) = fix(i→n(i) + 1, i2b(0) ').rest, i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = 0 ↔ i = 0 ∨ j = 0;% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ mklist(boolvar, m) = [] ↔ m = 0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + bytes0 = bytes + bytes1 ↔ bytes0 = bytes1;% ⊦ # mklist(boolvar, n) = n;