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Proof step 15 from proof int2bytes-rec-neg-02 (previous step)

i→n(i * 8) + 1 < # int2bits(j % 2 ^ (i * 8)), j + 2 ^ (i * 8) < 0, 0 < i ⊦ bits2bytes(int2bits(j / 2 ^ (i * 8) - 1) + fillsgn(i→n(i * 8) + 1, int2bits(j % 2 ^ (i * 8))).rest) = bits2bytes(int2bits(j / 2 ^ (i * 8) - 1)) + fix(i→n(i) + 1, int2bytes(j % 2 ^ (i * 8))).rest, j % 2 ^ (i * 8) = 0, # fillsgn(i→n(i * 8) + 1, int2bits(j % 2 ^ (i * 8))).rest % 8 = 0 ∧ fillsgn(i→n(i * 8) + 1, int2bits(j % 2 ^ (i * 8))).rest ≠ []

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ i < ~1 → (m < # int2bits(i) ↔ ¬ 0 ≤ i + 2 ^ (n→i(m) - 1)) subst: [i, m] → [j % 2 ^ (i * 8), i→n(i * 8) + 1] rotate: F spec: int2bits inst: name: int2bits-lslen-05

Additional information

Used terms: j % 2 ^ (i * 8), i→n(i * 8) + 1