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Proof step 157 from proof int2bytes-rec-neg-02 (previous step)

8 ≤ 8 * i→n(i) + 8 - # int2bits(j % 2 ^ (i * 8)), ((8 * i→n(i) + 8 - # int2bits(j % 2 ^ (i * 8))) + # int2bits(j % 2 ^ (i * 8))) % 8 = 0, 8 < (8 * i→n(i) + 8 - # int2bits(j % 2 ^ (i * 8))) + # int2bits(j % 2 ^ (i * 8)), # int2bits(j % 2 ^ (i * 8)) ≤ 8 * i→n(i) + 8, 0 < i, j % 2 ^ (i * 8) < 0, j + 2 ^ (i * 8) < 0, # int2bits(j % 2 ^ (i * 8)) < 8 * i→n(i) ⊦ j % 2 ^ (i * 8) = 0, mklist(true, 8 * i→n(i) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8)) = [], 1 + 8 * i→n(i) = # int2bits(j % 2 ^ (i * 8)), i = 0, bits2bytes(mklist(true, 8 * i→n(i) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8))) = (bits2bytes(mklist(true, 8)) + bits2bytes(restn(8, mklist(true, 8 * i→n(i) + 8 - # int2bits(j % 2 ^ (i * 8)))) + int2bits(j % 2 ^ (i * 8)))).rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m < n → m ≤ n;% ⊦ m + n ≤ m + n0 ↔ n ≤ n0;%n0 ≤ n ⊦ m ≤ n - n0 ↔ m + n0 ≤ n;% ⊦ m + n = n + m;% ⊦ m * n = n * m;% ⊦ m ≤ n → restn(m, mklist(boolvar, n)) = mklist(boolvar, n - m);% ⊦ i * j = j * i;