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Proof step 2 from proof int2bytes-rec-neg-02 (previous step)

0 < i, j + 2 ^ (i * 8) < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j) = int2bytes(j / 2 ^ (i * 8) - 1) + fix(i→n(i) + 1, int2bytes(j % 2 ^ (i * 8))).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 4:
0 < i, j + 2 ^ (i * 8) < 0 ⊦ j % 2 ^ (i * 8) = 0, bits2bytes(int2bits(j)) = int2bytes(j / 2 ^ (i * 8) - 1) + fix(i→n(i) + 1, int2bytes(j % 2 ^ (i * 8))).rest

Rule argument

name: int2bytes rotate: F subst: [i] → [j]

Additional information

Used terms: j