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Proof step 53 from proof int2bytes-rec-neg-02 (previous step)

# int2bits(j % 2 ^ (i * 8)) = i→n(i * 8), j % 2 ^ (i * 8) < 0, j < 0, j + 2 ^ (i * 8) < 0, 0 < i ⊦ j % 2 ^ (i * 8) = 0, 2 ^ (i * 8) = 0, i→n(i * 8) % 8 = 0, bits2bytes(int2bits(j / 2 ^ (i * 8) - 1) + int2bits(j % 2 ^ (i * 8))) = bits2bytes(int2bits(j / 2 ^ (i * 8) - 1)) + fix(i→n(i) + 1, int2bytes(j % 2 ^ (i * 8))).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: 0 ≤ i, 0 ≤ j ⊦ i→n(i) * i→n(j) = i→n(i * j) subst: [j, i] → [8, i] rotate: T spec: intnat inst: name: i2np

Additional information

Used simplifier rules: ⊦ i < j → ¬ j < i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i * j = j * i;%n ≠ 0 ⊦ (m * n) % n = 0;% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m; Used terms: 8, i