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Proof step 11 from proof int2bytes-rec-neg-03 (previous step)

j % 0 = 0, 2 ^ (i * 8) = 0, 0 < i, j < 0 ⊦ int2bytes(j / 0) = int2bytes((1 + j) / 0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ 0 < j → (i ^ j = 0 ↔ i = 0)

Rule argument

seq: ⊦ 0 < j → (i ^ j = 0 ↔ i = 0) subst: [j, i] → [i * 8, 2] rotate: F spec: int-pot inst: name: zero

Additional information

Used simplifier rules: ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: i * 8, 2