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Proof step 15 from proof int2bytes-rec-neg-03 (previous step)

j0 * 2 ^ (i * 8) + 1 - 2 ^ (i * 8) = (1 - 2 ^ (i * 8)) + j0 * 2 ^ (i * 8), 0 < i, 2 ^ (i * 8) * (j0 + 1) < 0 ⊦ 2 ^ (i * 8) = 0, int2bytes(j0) = int2bytes((j0 * 2 ^ (i * 8) + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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