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Proof step 29 from proof int2bytes-rec-neg-03 (previous step)

j + 1 - 2 ^ (i * 8) = (j + 1) + ~1 * 2 ^ (i * 8), 0 < i, j + 2 ^ (i * 8) < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

User applied rule insert equation

And obtained the following new goals

Proof step 30:
0 < i, j + 2 ^ (i * 8) < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes(((j + 1) + ~1 * 2 ^ (i * 8)) / 2 ^ (i * 8))

Rule argument

pos: left 1 flags: discard

Proof step 29 from proof int2bytes-rec-neg-03 (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

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