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Proof step 39 from proof int2bytes-rec-neg-03 (previous step)

0 < i, j + 2 ^ (i * 8) < 0 ⊦ ¬ ~1 ≤ j, j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information