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Proof step 46 from proof int2bytes-rec-neg-03 (previous step)

2 ^ (i * 8) = 0, 0 % 0 = 0, j < 0, j < ~1, 0 < i ⊦ j % 0 = 0, int2bytes(j / 0 - 1) = int2bytes((j + 1) / 0 + 0 / 0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 47:
⊦ 0 ≤ j → 2 ^ j ≠ 0

Rule argument

seq: ⊦ 0 ≤ j → 2 ^ j ≠ 0 subst: [j] → [i * 8] rotate: F spec: int-pot inst: name: two-zero

Additional information

Used simplifier rules: ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: i * 8