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Proof step 52 from proof int2bytes-rec-neg-03 (previous step)

(i0 * 2 ^ (i * 8) + j0) + 1 = (j0 + 1) + i0 * 2 ^ (i * 8), i0 * 2 ^ (i * 8) + j0 < ~1, 0 < i, i0 * 2 ^ (i * 8) + j0 < 0, j0 < 0, 0 < 2 ^ (i * 8) + j0, i0 ≤ 0, i0 < 2 ^ (i * 8) + j0, i0 < i, 2 ^ (i * 8) * (i0 + 1) + j0 < 0 ⊦ 2 ^ (i * 8) = 0, j0 = 0, int2bytes(i0 - 1) = int2bytes(((i0 * 2 ^ (i * 8) + j0) + 1) / 2 ^ (i * 8) - 1)

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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