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Proof step 12 from proof int2bytes-rec-neg-04 (previous step)

0 ≤ i * 8 ∧ j0 ≠ 0, 0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ 2 ^ (i * 8) = 0, bits2bytes(int2bits(j0) + mklist(false, i→n(i * 8))) = int2bytes(j0) + fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);% ⊦ 0 ≤ j → 2 ^ j ≠ 0;