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Proof step 15 from proof int2bytes-rec-neg-04 (previous step)

¬(# mklist(false, i→n(i * 8)) % 8 = 0 ∧ int2bits(j0) ≠ [] ∧ mklist(false, i→n(i * 8)) ≠ []), 0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ bits2bytes(int2bits(j0) + mklist(false, i→n(i * 8))) = int2bytes(j0) + fix(i→n(i) + 1, i2b(0) ').rest, j0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 < i → (i * j = 0 ↔ j = 0);% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ mklist(boolvar, m) = [] ↔ m = 0;% ⊦ int2bits(j) ≠ [];% ⊦ # mklist(boolvar, n) = n;