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Proof step 24 from proof int2bytes-rec-neg-04 (previous step)

i→n(i * 8) % 8 = 0 ∧ i→n(i * 8) ≠ 0, i→n(i * 8) % 8 = 0, 0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ j0 = 0, i = 0, mklist(i2b(0), i→n(i * 8) / 8) = fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
i→n(i * 8) % 8 = 0, 0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ j0 = 0, i = 0, mklist(i2b(0), i→n(i * 8) / 8) = fix(i→n(i) + 1, i2b(0) ').rest

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = 0 ↔ i = 0 ∨ j = 0;% ⊦ i→n(i) = 0 ↔ i = 0;