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Proof step 27 from proof int2bytes-rec-neg-04 (previous step)

0 ≤ i ∧ 0 ≤ 8, (i→n(i) * i→n(8)) % 8 = 0, 0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ j0 = 0, i = 0, mklist(i2b(0), (i→n(i) * i→n(8)) / 8) = fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0, 0 < i ⊦ j0 = 0, i = 0, mklist(i2b(0), i→n(i)) = fix(i→n(i) + 1, i2b(0) ').rest

Rule argument

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j);%n ≠ 0 ⊦ (m * n) / n = m;% ⊦ m * n = n * m;% ⊦ m0 * m * n = (m0 * m) * n;%n ≠ 0 ⊦ (m * n) % n = 0;