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Proof step 4 from proof int2bytes-rec-neg-04 (previous step)

¬ 2 ^ (i * 8) ≠ 0, j % 2 ^ (i * 8) = 0, j + 2 ^ (i * 8 - 1) < 0, 0 < i ⊦ int2bytes(j) = int2bytes(j / 2 ^ (i * 8)) + fix(i→n(i) + 1, i2b(0) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
2 ^ (i * 8) = 0, j % 0 = 0, j + 2 ^ (i * 8 - 1) < 0, 0 < i ⊦ int2bytes(j) = int2bytes(j / 0) + fix(i→n(i) + 1, i2b(0) ').rest

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;