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Proof step 32 from proof int2bytes-rec-neg-05 (previous step)

# int2bits(j) % 8 = 0, # int2bits(j) = 8 * i→n(i) + 8, 0 < i, j + 2 ^ (i * 8 - 1) < 0, 0 < j + 2 ^ (i * 8), 0 < 2 ^ (i * 8) + j, j < 0, # int2bits(j) ≤ 8 ⊦ j = 0, i2b(j) = i2b(~1), j = ~1

User applied rule insert equation

And obtained the following new goals

Proof step 33:
(8 * i→n(i) + 8) % 8 = 0, 0 < i, j + 2 ^ (i * 8 - 1) < 0, 0 < j + 2 ^ (i * 8), 0 < 2 ^ (i * 8) + j, j < 0, 8 * i→n(i) + 8 ≤ 8 ⊦ j = 0, i2b(j) = i2b(~1), j = ~1

Rule argument

pos: left 2 flags: discard

Proof step 32 from proof int2bytes-rec-neg-05 (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information