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Proof step 34 from proof int2bytes-rec-neg-05 (previous step)

8 * i→n(i) = 0, 0 < i, j + 2 ^ (i * 8 - 1) < 0, 0 < j + 2 ^ (i * 8), 0 < 2 ^ (i * 8) + j, j < 0 ⊦ j = 0, i2b(j) = i2b(~1), j = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ m0 * m = 0 ↔ m0 = 0 ∨ m = 0 subst: [m, m0] → [i→n(i), 8] rotate: F spec: nat-mult inst: name: zero-01

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ ~1 < i ↔ 0 ≤ i;% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i < j → ¬ j < i; Used terms: i→n(i), 8