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Proof step 13 from proof int2bytes-rec-neg-06 (previous step)

2 ^ (i * 8) ≠ 0, ∃ j0. j = j0 * 2 ^ (i * 8), 0 < i, j + 2 ^ (i * 8 - 1) < 0 ⊦ int2bytes(j / 2 ^ (i * 8)) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 < i, j0 * 2 ^ (i * 8) + 2 ^ (i * 8 - 1) < 0 ⊦ 2 ^ (i * 8) = 0, int2bytes(j0) = int2bytes((j0 * 2 ^ (i * 8) + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i * j * j0 = (i * j) * j0;%j ≠ 0 ⊦ (i * j) / j = i;% ⊦ i * j = j * i;