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Proof step 32 from proof int2bytes-rec-neg-06 (previous step)

0 < i, j + 2 ^ (i * 8 - 1) < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8)), ~(2 ^ (i * 8)) % 2 ^ (i * 8) = 0 ∧ ¬ ~1 ≤ j

User applied rule case distinction

And obtained the following new goals

Proof step 33:
0 < i, j + 2 ^ (i * 8 - 1) < 0 ⊦ ~(2 ^ (i * 8)) % 2 ^ (i * 8) = 0, j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))
Proof step 38:
0 < i, j + 2 ^ (i * 8 - 1) < 0 ⊦ ¬ ~1 ≤ j, j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1 - 2 ^ (i * 8)) / 2 ^ (i * 8))

Rule argument

pos: right 3

Proof step 32 from proof int2bytes-rec-neg-06 (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information