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Proof step 36 from proof int2bytes-rec-neg-06 (previous step)

2 ^ (i * 8) = 0, j + 2 ^ (i * 8 - 1) < 0, 0 < i ⊦ int2bytes(j / 0 - 1) = int2bytes((1 + j) / 0), j % 0 = 0, 0 % 0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 37:
⊦ 0 < j → (i ^ j = 0 ↔ i = 0)

Rule argument

seq: ⊦ 0 < j → (i ^ j = 0 ↔ i = 0) subst: [j, i] → [i * 8, 2] rotate: F spec: int-pot inst: name: zero

Additional information

Used simplifier rules: ⊦ 0 < i → (0 < i * j ↔ 0 < j);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: i * 8, 2