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Proof step 44 from proof int2bytes-rec-neg-06 (previous step)

¬ 2 ^ (i * 8) ≠ 0, ~(2 ^ (i * 8)) % 2 ^ (i * 8) = 0, 0 < i, j + 2 ^ (i * 8 - 1) < 0, j < ~1, j < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes(~(2 ^ (i * 8)) / 2 ^ (i * 8) + (j + 1) / 2 ^ (i * 8))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 45:
2 ^ (i * 8) = 0, 0 % 0 = 0, j < 0, j < ~1, j + 2 ^ (i * 8 - 1) < 0, 0 < i ⊦ j % 0 = 0, int2bytes(j / 0 - 1) = int2bytes((j + 1) / 0 + 0 / 0)

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;