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Proof step 47 from proof int2bytes-rec-neg-06 (previous step)

2 ^ (i * 8) ≠ 0, ~(2 ^ (i * 8)) % 2 ^ (i * 8) = 0, 0 < i, j + 2 ^ (i * 8 - 1) < 0, j < ~1, j < 0 ⊦ j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes(~(2 ^ (i * 8) / 2 ^ (i * 8)) + (j + 1) / 2 ^ (i * 8))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 48:
0 < i, j + 2 ^ (i * 8 - 1) < 0, j < ~1, j < 0 ⊦ 2 ^ (i * 8) = 0, j % 2 ^ (i * 8) = 0, int2bytes(j / 2 ^ (i * 8) - 1) = int2bytes((j + 1) / 2 ^ (i * 8) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;%i < 0 ⊦ (* i) + j = j - ~ i;%i ≠ 0 ⊦ i / i = 1;%i ≠ 0 ⊦ i % i = 0;%j ≠ 0 ⊦ ~ i % j = ~(i % j);