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Proof step 51 from proof int2bytes-rec-neg-06 (previous step)

(i0 * 2 ^ (i * 8) + j0) + 1 = (j0 + 1) + i0 * 2 ^ (i * 8), 0 < i, i0 * 2 ^ (i * 8) + j0 < ~1, i0 ≤ 0, i0 < i, i0 < 2 ^ (i * 8) + j0, (i0 * 2 ^ (i * 8) + j0) + 2 ^ (i * 8 - 1) < 0, i0 * 2 ^ (i * 8) + j0 < 0, j0 < 0, 0 < 2 ^ (i * 8) + j0 ⊦ 2 ^ (i * 8) = 0, j0 = 0, int2bytes(i0 - 1) = int2bytes(((i0 * 2 ^ (i * 8) + j0) + 1) / 2 ^ (i * 8) - 1)

User applied rule insert equation

And obtained the following new goals

Proof step 52:
0 < i, i0 * 2 ^ (i * 8) + j0 < ~1, i0 ≤ 0, i0 < i, i0 < 2 ^ (i * 8) + j0, (i0 * 2 ^ (i * 8) + j0) + 2 ^ (i * 8 - 1) < 0, i0 * 2 ^ (i * 8) + j0 < 0, j0 < 0, 0 < 2 ^ (i * 8) + j0 ⊦ 2 ^ (i * 8) = 0, j0 = 0, int2bytes(i0 - 1) = int2bytes(((j0 + 1) + i0 * 2 ^ (i * 8)) / 2 ^ (i * 8) - 1)

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: ⊦ i * j = j * i;