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Proof step 2 from proof int2bytes-rec-neg-256-01 (previous step)

i < ~256, i < 0 ⊦ int2bytes(i) = int2bytes(i / 256 - 1) + int2bytes(i % 256).last ', i % 256 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
j < ~(2 ^ (i * 8)), 0 < i, j % 2 ^ (i * 8) ≠ 0 ⊦ int2bytes(j) = int2bytes(j / 2 ^ (i * 8) - 1) + fix(i→n(i + 1), int2bytes(j % 2 ^ (i * 8))).rest
Proof step 4:
i < ~(2 ^ (0 +1 * 8)) ∧ 0 < 0 +1 ∧ i % 2 ^ (0 +1 * 8) ≠ 0, i < ~256, i < 0 ⊦ int2bytes(i / 2 ^ (0 +1 * 8) - 1) + fix(i→n(0 +1 + 1), int2bytes(i % 2 ^ (0 +1 * 8))).rest = int2bytes(i / 256 - 1) + int2bytes(i % 256).last ', i % 256 = 0

Rule argument

name: int2bytes-rec-neg-02 rotate: F subst: [j, i] → [i, 0 +1]

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: i, 0 +1