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Proof step 2 from proof int2bytes-rec-pos-01 (previous step)

i % 256 = 0, 0 < i, 255 < i ⊦ int2bytes(i) = int2bytes(i / 256) + i2b(0) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
255 < i ⊦ int2bytes(i) = int2bytes(i / 256) + int2bytes(i % 256).last '

Rule argument

name: int2bytes-rec-pos rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: int2bytes-byte: ~128 ≤ i, i < 128 ⊦ int2bytes((* i)) = i2b(i) ';% ⊦ bytes + bytes0 = bytes + bytes1 ↔ bytes0 = bytes1;% ⊦ by ' = by0 ' ↔ by = by0;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by '.last = by;%~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i2b((* i)) = i2b((* j)) ↔ i = j; Used terms: i