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Proof step 5 from proof int2bytes-rec-pos-03 (previous step)

0 ≤ i % 256, 0 < i % 256, 0 < i, 128 ≤ i % 256, 255 < i ⊦ int2bytes(i % 256).last ' = int2bytes(i % 256).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
127 < i, i ≤ 255 ⊦ int2bytes(i) = i2b(0) ' + i2b(i - 256) '

Rule argument

name: int2bytes-le255 rotate: F subst: [i] → [i % 256]

Additional information

Used simplifier rules: ⊦ ¬ 255 < i % 256;% ⊦ ¬ i ≤ j ↔ j < i;%i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;% ⊦ (bytes + by ').last = by;% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ (by ' + bytes).rest = bytes;% ⊦ by ' = by0 ' ↔ by = by0; Used terms: i % 256