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Proof step 13 from proof int2bytes-rec-pos-04 (previous step)

0 ≤ i % 256 ∧ i % 256 ≤ 127, i % 256 < 128, 256 ≤ i, 0 < i, 0 ≤ i ⊦ i2b(i % 256) ' = fix(2, i2b(i % 256) ').rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
i % 256 ≤ 127, 256 ≤ i, 0 < i, 0 ≤ i ⊦ i2b(i % 256) ' = fix(2, i2b(i % 256) ').rest

Rule argument

Additional information

Used simplifier rules: j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0);% ⊦ 0 < j ∧ 0 ≤ i → 0 ≤ i % j;