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Proof step 2 from proof int2bytes-rec-pos-04 (previous step)

256 ≤ i, 0 < i, 0 ≤ i ⊦ int2bytes(i) = int2bytes(i / 256) + fix(2, int2bytes(i % 256)).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
255 < i, i % 256 < 128 ⊦ int2bytes(i) = int2bytes(i / 256) + int2bytes(i % 256)
Proof step 4:
¬(255 < i ∧ i % 256 < 128), 256 ≤ i, 0 < i, 0 ≤ i ⊦ int2bytes(i) = int2bytes(i / 256) + fix(2, int2bytes(i % 256)).rest
Proof step 10:
255 < i ∧ i % 256 < 128, 256 ≤ i, 0 < i, 0 ≤ i ⊦ int2bytes(i / 256) + int2bytes(i % 256) = int2bytes(i / 256) + fix(2, int2bytes(i % 256)).rest

Rule argument

name: int2bytes-rec-pos-02 rotate: F subst: [i] → [i]

Additional information

Used terms: i