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Proof step 5 from proof int2bytes-rec-pos-04 (previous step)

0 < i, 0 < i % 256, 255 < i, 128 ≤ i % 256, 0 ≤ i, 256 ≤ i ⊦ int2bytes(i) = int2bytes(i / 256) + fix(2, int2bytes(i % 256)).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
255 < i, 128 ≤ i % 256 ⊦ int2bytes(i) = int2bytes(i / 256) + int2bytes(i % 256).rest
Proof step 7:
255 < i ∧ 128 ≤ i % 256, 0 < i, 0 < i % 256, 255 < i, 128 ≤ i % 256, 0 ≤ i, 256 ≤ i ⊦ int2bytes(i / 256) + int2bytes(i % 256).rest = int2bytes(i / 256) + fix(2, int2bytes(i % 256)).rest

Rule argument

name: int2bytes-rec-pos-03 rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j; Used terms: i