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Proof step 1 from proof int2bytes-rec-pos-any (conclusion)

2 ^ (i * 8) ≤ j, 0 < i ⊦ int2bytes(j) = int2bytes(j / 2 ^ (i * 8)) + fix(i→n(i + 1), int2bytes(j % 2 ^ (i * 8))).rest

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ int2bytes(i) = bits2bytes(int2bits(i))
Proof step 3:
2 ^ (i * 8) ≤ j, 0 < i ⊦ bits2bytes(int2bits(j)) = int2bytes(j / 2 ^ (i * 8)) + fix(i→n(i + 1), int2bytes(j % 2 ^ (i * 8))).rest

Rule argument

name: int2bytes rotate: F subst: [i] → [j]

Additional information

Used terms: j