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Proof step 189 from proof int2bytes-rec-pos-any (previous step)

i→n(i * 8) % 8 = 0, b2i(i2b(bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8)))))) < 0, 0 ≤ j % 2 ^ (i * 8), 2 ^ (i * 8) ≤ j, # int2bits(j % 2 ^ (i * 8)) < i→n(i * 8), 8 < # int2bits(j % 2 ^ (i * 8)), 1 < i, 0 < i ⊦ ¬ 127 < bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8)))), # int2bits(j % 2 ^ (i * 8)) % 8 = 0, i = 0, # int2bits(j % 2 ^ (i * 8)) = i→n(i * 8), i→n(i * 8) + 1 = # int2bits(j % 2 ^ (i * 8)), mklist(false, i→n(i * 8) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8)) = [], bits2bytes(mklist(false, i→n(i * 8) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8))) = fix (i→n(i) + 1, i2b(bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8))))) ' + bits2bytes(restn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8))))) .rest

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 190:
i→n(i * 8) % 8 = 0, 0 < bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8)))), 0 < i, 1 < i, 8 < # int2bits(j % 2 ^ (i * 8)), # int2bits(j % 2 ^ (i * 8)) < i→n(i * 8), 2 ^ (i * 8) ≤ j, 0 ≤ j % 2 ^ (i * 8), b2i(i2b(bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8)))))) < 0, 127 < bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8)))) ⊦ bits2bytes(mklist(false, i→n(i * 8) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8))) = fix (i→n(i) + 1, i2b(bits2int(firstn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8))))) ' + bits2bytes(restn(# int2bits(j % 2 ^ (i * 8)) % 8, int2bits(j % 2 ^ (i * 8))))) .rest, mklist(false, i→n(i * 8) - # int2bits(j % 2 ^ (i * 8))) + int2bits(j % 2 ^ (i * 8)) = [], i→n(i * 8) + 1 = # int2bits(j % 2 ^ (i * 8)), # int2bits(j % 2 ^ (i * 8)) = i→n(i * 8), i = 0, # int2bits(j % 2 ^ (i * 8)) % 8 = 0

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) < j → (* i0) < j;% ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward)% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i * j = j * i;