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Proof step 29 from proof int2bytes-rec-pos-any (previous step)

i→n(i * 8 + 1) = # int2bits(j % 2 ^ (i * 8)), i→n(i * 8 + 1) ≤ 1 + 8 * i→n(i), 0 ≤ j, 0 ≤ i, 0 < i, 2 ^ (i * 8) ≤ j, 0 < j ⊦ bits2bytes(int2bits(j / 2 ^ (i * 8)) + (mklist(¬ 0 ≤ j % 2 ^ (i * 8), 1 + 8 * i→n(i) - i→n(i * 8 + 1)) + int2bits(j % 2 ^ (i * 8))).rest) = int2bytes(j / 2 ^ (i * 8)) + fix(i→n(i) + 1, int2bytes(j % 2 ^ (i * 8))).rest, # int2bits(j % 2 ^ (i * 8)).rest % 8 = 0 ∧ int2bits(j % 2 ^ (i * 8)).rest ≠ []

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 2

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